Java Strings Introduction – Hacker Rank Solution ~ Multiplex Coder

Objective

“A string is traditionally a sequence of characters, either as a literal constant or as some kind of variable.

This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = "Hello World!"

The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters, A and B, perform the following operations:

Sum the lengths of A and B .
Determine if A is lexicographically larger than B (i.e.: does B come before A in the dictionary?).
Capitalize the first letter in A and B and print them on a single line, separated by a space.

Input Format

The first line contains a string A . The second line contains another string B . The strings are comprised of only lowercase English letters.

Output Format

There are three lines of output:
For the first line, sum the lengths of A and B.
For the second line, write Yes if A is lexicographically greater than B otherwise print No instead.
For the third line, capitalize the first letter in both A and B and print them on a single line, separated by a space.

Sample Input 0

hello
java

Sample Output 0

9
No
Hello Java

Explanation 0

String A is “hello” and B is “java”.

A has a length of 5 , and B has a length of 4; the sum of their lengths is 9 .
When sorted alphabetically/lexicographically, “hello” precedes “java”; therefore, is not greater than and the answer is No.

When you capitalize the first letter of both A and B and then print them separated by a space, you get “Hello Java”.

Java Strings Introduction – Hacker Rank Solution

Code:

import java.util.Scanner;

public class Solution {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

String A = sc.next();

String B = sc.next();

System.out.println(A.length() + B.length());

if (A.compareTo(B) > 0) {

System.out.println("Yes");

} else {

System.out.println("No");

}

A = A.substring(0, 1).toUpperCase() + A.substring(1);

B = B.substring(0, 1).toUpperCase() + B.substring(1);

System.out.println(A + " " + B);

}

Disclaimer: The above Problem (Java Strings Introduction) is generated by Hackerrank but the Solution is Provided by MultiplexCoder. This tutorial is only for Educational and Learning purposes.

Java Strings Introduction – Hacker Rank Solution

Objective

Java Strings Introduction – Hacker Rank Solution

Related Post