Finding the percentage in Python – Hacker Rank Solution

 



The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal.

Example
marks key:value pair are

‘alpha’:[20,30,40]

‘beta’:[30,50,70]

query_name = ‘beta’

The query_name is ‘beta’. beta’s average score is (30+50+70)/3=50.0.

Input Format

The first line contains the integer n, the number of students’ records. The next n lines contain the names and marks obtained by a student, each value separated by a space. The final line contains query_name, the name of a student to query.

Constraints

  • 2 <= N <= 10
  • 0 <= Marks <= 100
  • Length of marks arrays = 3

Output Format

Print one line: The average of the marks obtained by the particular student correct to 2 decimal places.

Sample Input 0

3
Krishna 67 68 69
Arjun 70 98 63
Malika 52 56 60
Malika

Sample Output 0

56.00

Explanation 0

Marks for Malika are  whose average is 

Sample Input 1

2
Harsh 25 26.5 28
Anurag 26 28 30
Harsh

Sample Output 1

26.50

Finding the percentage in Python – Hacker Rank Solution

Code:

if __name__ == '__main__':
    n = int(input())
    marks = {}

    for _ in range(n):
        name, *line = input().split()
        scores = list(map(float, line))
        scores=sum(scores)/3
        marks[name] = scores
    a = input()    
    
    print('%.2f' % marks[a])

Disclaimer: The above Problem (Finding the percentage in Python – Hacker Rank Solution) is generated by Hackerrank but the Solution is Provided by MultiplexCoder. This tutorial is only for Educational and Learning purposes.
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