Nested Lists in Python – Hacker Rank Solution ~ Multiplex Coder

Given the names and grades for each student in a class of N students, store them in a nested list and print the name(s) of any student(s) having the second lowest grade.

Note: If there are multiple students with the second lowest grade, order their names alphabetically and print each name on a new line.

Example

The ordered list of scores is , so the second lowest score is . There are two students with that score: . Ordered alphabetically, the names are printed as:

alpha
beta

Input Format

The first line contains an integer, , the number of students.
The subsequent lines describe each student over lines.
– The first line contains a student’s name.
– The second line contains their grade.

Constraints

2 <= N <=5
There will always be one or more students having the second-lowest grade.

Output Format

Print the name(s) of any student(s) having the second lowest grade in Physics; if there are multiple students, order their names alphabetically and print each one on a new line.

Sample Input 0

5
Harry
37.21
Berry
37.21
Tina
37.2
Akriti
41
Harsh
39

Sample Output 0

Berry
Harry

Explanation 0

There are 5 students in this class whose names and grades are assembled to build the following list: python students = [[‘Harry’, 37.21], [‘Berry’, 37.21], [‘Tina’, 37.2], [‘Akriti’, 41], [‘Harsh’, 39]]
The lowest grade of 37.2 belongs to Tina. The second-lowest grade of 37.21 belongs to both Harry and Berry, so we order their names alphabetically and print each name on a new line.

Nested Lists in Python – Hacker Rank Solution

Code:

if __name__ == '__main__':

students = []

for _ in range(int(input())):

name = input()

score = float(input())

students.append([name,score])

x = 99999

for i in range(len(students)):

if x > float(students[i][1]):

x = float(students[i][1])

y = 999999

for i in range(len(students)):

if float(students[i][1]) > float(x) and y > float(students[i][1]):

y = float(students[i][1])

runner = []

for i in range(len(students)):

if float(students[i][1]) == float(y):

runner.append(students[i][0])

runner = sorted(runner)

for i in range(len(runner)):

print(runner[i])

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Nested Lists in Python – Hacker Rank Solution

Nested Lists in Python – Hacker Rank Solution

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