Functions in C – Hacker Rank Solution

 

Objective

In this challenge, you will learn simple usage of functions in C. Functions are a bunch of statements glued together. A function is provided with zero or more arguments, and it executes the statements on it. Based on the return type, it either returns nothing (void) or something.
A sample syntax for a function is

1 2 3 4 5 6 7return_type function_name(arg_type_1 arg_1, arg_type_2 arg_2, …) { … … … [if return_type is non voidreturn something of type `return_type`; }

For example, a function to read four variables and return the sum of them can be written as

1 2 3 4 5 6 7 8int sum_of_four(int a, int b, int c, int d) { int sum = 0; sum += a; sum += b; sum += c; sum += d; return sum; }

Task

You have to write a function int max_of_four(int a, int b, int c, int d) which reads four arguments and returns the greatest of them.

+= : Add and assignment operator. It adds the right operand to the left operand and assigns the result to the left operand.

a += b is equivalent to a = a + b;

Input Format

Input will contain four integers –  a,b,c,d one in each line.

Output Format

Print the greatest of the four integers.
Note: I/O will be automatically handled.


Sample Input

3
4
6
5

Sample Output

6





Functions in C – Hacker Rank Solution

Code:

#include <stdio.h>
int max_of_four(int,int,int,int);
/*
Add `int max_of_four(int a, int b, int c, int d)` here.
*/
// Functions in C - Hacker Rank Solution START

int max_of_four(int a,int b,int c,int d)
{
    int gre;
    if(a>b && a >c && a >d)
        gre = a;
    else if(b>a && b>c && b>d)
        gre = b;
    else if(c>a && c>b && c>d)
        gre = c;
    else if(d>a && d>b && d>c)
        gre = d;
    else if(a=b=c=d)
        gre = a;
return gre;
}
// Functions in C - Hacker Rank Solution END

int main() {
    int a, b, c, d;
    scanf("%d %d %d %d", &a, &b, &c, &d);
    int ans = max_of_four(a, b, c, d);
    printf("%d", ans);
    
    return 0;
}

Disclaimer: The above Problem (Functions in C) is generated by Hackerrank but the Solution is Provided by MultiplexCoder. This tutorial is only for Educational and Learning purposes. Authority if any of the queries regarding this post or website fill the following contact form thank you.
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